1. The output force of the cylinder has nothing to do with the stroke length, such as:
Air pressure 0.5Mpa (5.0985811 kilogram force/square centimeter (kgf/cm2))
Bore diameter 100mm (5cm)
Cylinder cross-sectional area=3.14X(10/2)^2=78.5(square centimeters)
So, the theoretical output under 0.5Mpa = 5.0985811*78.5 = 400.24 (kg force) can be directly referred to the output table below
But this is only a theoretical contribution, the actual situation will depend on the working conditions
2. Actual output force of the cylinder N=A*F
1. (Assume that the cylinder operates at 50~500mm/s, 100-bore cylinder. The theoretical output is 400 kg at 0.5Mpa air pressure, and 400 kg Contribute)
For static loads (such as clamping, low-speed riveting, etc.), F2 resistance is very small, A≤0.7;
For horizontal or vertical movement with cylinder speed in the range of 50~500mm/s, A≤0.5;
For actions where the cylinder speed is greater than 500mm/s, F2 has a great influence, A≤0.3.
2. For example, we estimate that a cylinder with a bore diameter of Φ40mm needs to be selected for a certain occasion. This is the bottom line, but there is no need to say, give a safety factor, and then choose a " "Accurate" cylinder diameter, the actual approach should be based on various considerations, you may choose a cylinder diameter of Φ50mm or Φ63mm or even Φ100mm
The determination of the diameter of the cylinder needs to be determined according to the load size, operating speed and working pressure
(1) Determine the relevant load weight: The load conditions include the weight of the workpiece, fixture, guide rod and other movable parts.
(2) Select the air pressure to be used: the compressed air pressure of the supply cylinder
(3) Action direction: Determine the cylinder action direction (up, down, horizontal)
3. Standard single-rod cylinder theoretical output force table
4. Double-rod cylinder theoretical output force table
Five. Three-rod cylinder load and torque force table
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